log[5](x^2+4x)=1

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Solution for log[5](x^2+4x)=1 equation:


Simplifying
log[5](x2 + 4x) = 1

Reorder the terms:
glo * 5(4x + x2) = 1

Reorder the terms for easier multiplication:
5glo(4x + x2) = 1
(4x * 5glo + x2 * 5glo) = 1
(20glox + 5glox2) = 1

Solving
20glox + 5glox2 = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + 20glox + 5glox2 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 20glox + 5glox2 = 0

The solution to this equation could not be determined.

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